100x^2+300x-400=0

Solution for 100x^2+300x-400=0 equation:

100x^2+300x-400=0

a = 100; b = 300; c = -400;
Δ = b2-4ac
Δ = 3002-4·100·(-400)
Δ = 250000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{250000}=500$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(300)-500}{2*100}=\frac{-800}{200}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(300)+500}{2*100}=\frac{200}{200}
=1
$